Question

已 知角a的终边在直线y=根号3/3x上,则sina=?tana=? 请写出详细过程

Answer 1

∵y=(√3/3)x=(tanα)x.

∴tanα=√3/3.

α=kπ+π/6.k∈Z,

sin(kπ+π/6)=sinπ/6=1/2 k=2n,n∈N(0,1,2,3,...) ;

=-sinπ/6=-1/2,k=2n+1,n∈N (0,1,2,3,...)

tanα=tan(kπ+π/6)=tanπ/6=√3/3 ,k∈Z.