(2x²+2x+1)-(x²-3x+2)
=2x²+2x+1-x²+3x-2
=(2x²-x²)+(2x+3x)+(1-2)
=x²+5x-1
原题的被减式为:x²+5x-1
(x²+5x-1)-(x²-3x+2)
=x²+5x-1-x²+3x-2
=(x²-x²)(+(5x+3x)-(1+2)
=8x-3
原题的正确结果是:8x-3
(2x²+2x+1)-(x²-3x+2)
=2x²+2x+1-x²+3x-2
=(2x²-x²)+(2x+3x)+(1-2)
=x²+5x-1
原题的被减式为:x²+5x-1
(x²+5x-1)-(x²-3x+2)
=x²+5x-1-x²+3x-2
=(x²-x²)(+(5x+3x)-(1+2)
=8x-3
原题的正确结果是:8x-3