sin2π/3· cos3π/2· tanπ/4=
1个回答
因为cos3pi/2=0 所以整个等于0
手机提问的朋友在客户端上评价点【满意】即可.
互相帮助,祝共同进步!
相关问题
求值:2cosπ/2-tanπ/4+3/4tan²π/6-sinπ/6+cos²π/6+sin3π/
sin-3π/4= cos11π/6= tan13π/4= sin7π/2= cos-3π/2= sin10π/3=
(1)计算:2cos[π/2]+tan[π/4]+3sin0+cos2[π/3]+sin[3π/2];
sin^2(π/4)-cos^2(π/2)+2tan^3(π/4)
计算sin(-7π/2)+tanπ-2cos0+tan9π/4-sin7π/3
tan(a-4π)cos(π+a)sin^2(a+3π)/tan(3π+a)cos^2(2/5π+2)=0.5,求tan
化简sin(a+3π/2)sin(3π/2-a)tan^2(2π-a)tan(π-a)/cos(π/2-a)cos(π/
求值sin(π/2)*sin(π/3)+2cos(-π/2)-根号3*tan(π/3)
sin^2π/3+cos^43π/2+tan^2π/3=
tan(π-α)*sin^2(α+π/2)*cos(2π-α)/cos^3(-α-π)*tan(2π-α) sin^2就