Question

(2x-4分之x的平方-5x+6)+(x-1分之x的平方-4x+3),其中x=5

Answer 1

(x²-5x+6)/(2x-4)+(x²-4x+3)/(x-1)

=(x-2)(x-3)/2(x-2)+(x-1)(x-3)/(x-1)

=(x-3)/2+(x-3)

=3(x-3)/2

=3(5-3)/2

=3