Question

一道数学数列问题http://www.***.com/math2/ques/detail/99fcfe0e-7a19

Answer 1

答：a(kn-1)=akn-k

∵(akn)^2-(ak(n-1))^2=(akn)^2-(akn-1)^2+(akn-1)^2-(akn-2)1^2+……+(akn-k+1)^2-(akn-k)^2

=(k-1)p

∴成立