Question

设R为半径,d为弦长,h为弧长,则R=d/(2*sin(h*180/2pi*R)),d=2米 h=3米求R=?

Answer 1

d=2米,h=3米

Rn+1=(1+(d-2*Rn*SIN(h/(2*Rn)))/(d-h*COS(h/(2*Rn))))*Rn

R0=0.5

R1=0.687

R2=0.849

R3=1.959

R4=0.999

R5=1.003

R6=1.003

半径R=1.003米