Question

-2√a二次方-b二次方/6x五次方*√x二次方/3a+3b/4/5√a-b/b怎么算?

Answer 1

原式=-2√[x(a+b)(a-b)]6/|x³|*|x|/√[3(a-b)]*5/4*√b/√(a-b)

=-5/2x²*√[x(a+b)(a-b)/6*3(a-b)*b/(a-b)]

=-5/4x²*√2[(a²bx-3b³x)]

=-5√2[(a²bx-3b³x)]/(4x²)