Question

求函数y= 根号3 sinx/2-cosx的值域

Answer 1

y=√7/2[sinx*√21/7-cosx*2√7/7)

令cosθ=√21/7,sinθ=2√7/7),

y=√7/2sin(x-θ),

值域：y∈[-√7/2,√7/2].