7cos270°+3sin270°+tan765°=7cos(180°+90°).=-7cos90°-3sin90°+t
1个回答
7cos270°+3sin270°+tan765°
=0-3 +tan45° (cos270°=0,sin270°=-1)
=-3+1
=-2
相关问题
计算7cos270°+3sin270°+tan765°
三角函数问题请问一下sin90,sin-90,cos180,sin270,cos360,tan90,tan180,tan
6Sin(-90°)+3Sin0°-8Sin270°+12Cos180° 10Cos270°+4Sin0°+9tan0°
6Sin(-90°)+3Sin0°-8Sin270°+12Cos180°=?
5sin90°+2sin0°-3sin270°+10cos180°
5sin90°+2cos0°+3sin270°+10cos180°求解答,
sinπ/3+cosπ/2=5sin90°+2sin0°-3sin270°+10cos180°=
(1) 6 sin(-90°)+3 sin 0°-8 sin 270°+12 cos 180°
计算:6sin(-90°)+3sin0°-8sin270°+12cos180°
sin90 sin180 cos90 cos180 tan90 tan180分别是多少?