是的
cos2x=2cos²x-1
所以后面-2cos²x+1=-cos2x
你的符号错了
fx=-根号2sin（2x+π/4）+6sinxcosx-2cos²x+1
1个回答
相关问题
-
化简fx=-根号2sin（2x+π/4）+6sinxcosx-2cos²x+1 x属于R
-
fx=cos4x-2sinxcosx-sin4x
-
化简f(x)=sin(x-π/4)+4*（根号2）sinxcosx-cos(x+π/4)-2
-
函数fx=sinxcosx（x-π/4）+sin（π/2+x）sin（x-π/4）的图像
-
(1-cos2x)+sin2x=根号2(sin2x cosπ/4-cos2x sinπ/4)+1
-
fx=1-2sin^2(x+π/4)+2sin(x+π/8)cos(x+π/8)
-
2√3sinxcosx+2cos²x-1 =√3sin2x+cos2x =2sin(2x+π/6)
-
f[X]=sin[X-π/4]+4根号2×sinXcosX—cos[X+π/4]—2 X∈[π/4,π/2]求函数最大值
-
已知函数fx=cos(2x-π/3)+2sin(x-π/4)sin(x+π/4)
-
fx=2根号3sinxcosx+cos2x+1化简