x=3.5
SO2:0.01%*22400L=2.24L即0.1mol,根据方程:
ZnFe2OX + (2-X/2)SO2=ZnFe2O4 +(2-X/2)S
(177+16X)g (2-X/2)mol
93.2g 0.1mol
解得x=3.5