log3(8)=log3(2)^3=3log3(2),所以原式=3
算式log3 2分之log3 8=什么?
3个回答
相关问题
-
(log2(3)+log8(9))x(log3(4)+log9(8)+log3(2))
-
log4(3)-log4(12)-log8(4) =log4(3/12)- log8( 8^(2/3) ) log8(
-
(log4 3+log8 3)*(log3 2+log4 2)
-
(log2 3+log8 9)(log3 4+log9 8+log3 2)的运算过程
-
(log3 4+log3 8)(log2 3+log2 9)+(log3 根号2)(log9 7)/(log1/3 7)
-
(log(4)3+log(8)3)(log(3)2+log(9)8) 怎么个思路
-
2log3^2-log3^(32/9)+log3^8
-
2log3^2-log3^(32/9)+log3^8-5log5^3=
-
求值(log3(2)+log9(2))*(log4(3)+log8(3))
-
NO.1 (log3 2 + log9 2) (log4 3 + log8 3)