这个问题很简单 x^2-xy-2y^2=0变为x^2-2xy+xy-2y^2=0变为x(x+y)-2y(x+y)=0变为(x-2y)(x+y)=0
x^2-xy-2y^2=0是怎么变成(x+y)(x-2y)=0求解,
3个回答
相关问题
-
x2+Xy-2Y2=0是如何变成(x-y)(x+2Y)
-
求解常微分方程 y+2xy'+(x^2)y''=0 坐等…
-
如果x+y=0,xy=-7,x2y+xy2=______,x2+y2=______.
-
已知x^2-3xy+2y^2=0(xy≠0),则x/y+y/x=
-
常微分方程求解,重赏![2xy+(x^2)y+(y立方)/3]dx +(x^2 +y^2)dy = 0
-
求解微分方程(xy^2+x)dx+(y-x^2y)dy=0,y(2)=1的通解
-
知x2-xy-2y2=0,且x≠0,y≠0,求代数式x2−2xy−5y2x2+2xy+5y2的值.
-
已知x^2+xy-2y^2=0 (x不等于0,y不等于0),求x/y-y/x-(x^2+y^2)/xy的值
-
x^2+y^2=3xy xy≠0 求x^2 y^-2 + x^-2 y^2
-
解方程组x^2+y^2-x-y=0 xy-2x-2y+8=0