(1)t=10min=600s,P=60kw=60000w
W=Pt=60000w x 600s=36000000J
(2)匀速行驶,说明二力平衡,牵引力大小等于阻力
f=F=W/S=W/(vt)=36000000J/(20m/s x 600s)=3000N(
答:10分钟内汽车发动机做功36000000J,这辆汽车受到的阻力是3000牛.
(1)t=10min=600s,P=60kw=60000w
W=Pt=60000w x 600s=36000000J
(2)匀速行驶,说明二力平衡,牵引力大小等于阻力
f=F=W/S=W/(vt)=36000000J/(20m/s x 600s)=3000N(
答:10分钟内汽车发动机做功36000000J,这辆汽车受到的阻力是3000牛.