(根号a加根号b加1)乘以(1减根号a加根号b)减

(根号a加根号b加1)乘以(1减根号a加根号b)减(根号a加根号b)的平方等于多少

1个回答

原式=[(√b+1)+√a][(√b+1)-√a]-(a+2√ab+b)
=(√b+1)²-a-a-2√ab-b
=b+2√b+1-2a-2√ab-b
=2√b+1-2a-2√a