加急!】把下列多项式,】4(3x+y)²-(2x-y)² -m³+2m²-m 4xy²+4x²y+y³
5个回答
4(3x+y)²-(2x-y)² =(4x+3y)(8x+y)
-m³+2m²-m =-m(m-1)²
4xy²+4x²y+y³ =y(y+2x)²
(阳,是同学旳话勼给涐哦)
相关问题
关于x,y得多项式(5m+1)x^2y+(4n-2)xy^2-3x+y-(-2m-6)x^2y+(3-3n)xy^2 不
多项式4x^3y-m可以分解为4xy(x^2-y^2+ab),那么M等于多少?
x的平方-4xy+4y的平方-3x+6y=(x-2y)(x-2y+m),那么m=
若多项式5x*x-2mxy-3y*y+4xy-3x+1中不含xy项,求(-(m*m*m)+2(m*m)-m+1)-(m*
多项式有:①x2+xy+y2;②a2-a+[1/4];③[1/16]m2+m+1;④x2-xy+[1/4]y2;⑤m2+
若多项式x^4+mx^2y^2+y^4和2x^4-3x^2y^2-2Y4的公因式是2x^2+y^2求(1)m^2-m-2
4m²(2x-3y)²-m²(3x-2y)²=?
把多项式(1-x²)(1-y²)-4xy分解因式的结果是(xy+m)(xy-1-x-y),则m=__
已知x-2y=m-4和3x+2y=3m的x,y也满足x+4Y=2m+3,那么m=多少
分解因式:2m^3 - 8m (x+2)(x+4)+ x^2 -4 4(x-y)^2 - 2(y-x)^3 x^2 (y