弧长C=230,弦长L=200,求半径R?
Rn+1=(1+(L-2*Rn*SIN(C/(2*Rn)))/(L-C*COS(C/(2*Rn))))*Rn
R0=100
R1=116.452
R2=125.349
R3=127.294
R4=127.37
R5=127.37
R=127.37
弧长C=230,弦长L=200,求半径R?
Rn+1=(1+(L-2*Rn*SIN(C/(2*Rn)))/(L-C*COS(C/(2*Rn))))*Rn
R0=100
R1=116.452
R2=125.349
R3=127.294
R4=127.37
R5=127.37
R=127.37