题意不清楚啊,“当x∈(0,1)时,f(x)=2的x次方”?
f(log2 24)=f(log2(16) + log2(3/2)) = f(4+log2(3/2)) = f(log2(3/2));
由于当x∈(0,1)时,f(x)=2的x次方,
又2^0 < 3/2 < 2^1 ,故0 < log2(3/2) < 1;
因此由题设f(log2(3/2)) = 2^(log2(3/2)) = 3/2
题意不清楚啊,“当x∈(0,1)时,f(x)=2的x次方”?
f(log2 24)=f(log2(16) + log2(3/2)) = f(4+log2(3/2)) = f(log2(3/2));
由于当x∈(0,1)时,f(x)=2的x次方,
又2^0 < 3/2 < 2^1 ,故0 < log2(3/2) < 1;
因此由题设f(log2(3/2)) = 2^(log2(3/2)) = 3/2