6(3x-2)-5(2-3x)+(3x-2)=------(3x-2)
2个回答
6(3x-2)-5(2-3x)+(3x-2)=
6(3x-2)+5(3x-2)+(3x-2)=
(6+5+1)(3x-2)
=12(3x-2)
相关问题
设M={x|x-2/3+x-3/2=3/x-2+2/x-3}N={x|x-6/5+x-5/6=5/x-6+6/x-5}求
(1){5x-3y=5 6x+2y=6 (2){3x+2y=5x+2 2(3x+2y)=2x+8(3){x+3/3+y+
6-3(x+2/3)+2/3 -x=-2/5x+1 2x-1/3=-x/3+2
21-x/2+x/3-2x/5=x x+2/3+x=10-2x/7 9-3x-2/5=7-3x/6
计算 ①2(x^2)^3*x^2-3(x^3)^2+5x^2*x^6 ②(-2^2)*(-2)^2
2(x+1)=3x-3 (8+x)*2=3*(x+5) 2(x+6)=3x+14 (
若x=-1/6,求代数式2(3x^3-4x^2+5x-6)-7(3x^2-5x-7)+10(-3x^3+2x^2-4x-
(1/3)6-6x=24,4x+5=3x+3-2x,3-(5x+7)/2=(x+17)/4,(3x-1)/3=(x+2)
(6x+2)/(x^2+3x+2)=5-(2x^2+6x+4)/(3x+1)
3x^2-2x+5-6x^2+3x-9