∵m+n=-2005 mn=7
∴以m,n为根的方程为xx+2005x+7=0(满足m+n=-2005 mn=7)
即mm+2005m+7=0;nn+2005n+7=0
(mm+2004m+6)(nn+2006n+8)
=(mm+2005m+7-m-1)(nn+2005n+7+n+1)
=(0-m-1)(0+n+1)
=-(m+1)(n+1)
=-(mn+m+n+1)
=-(7-2005+1)
=1997
∵m+n=-2005 mn=7
∴以m,n为根的方程为xx+2005x+7=0(满足m+n=-2005 mn=7)
即mm+2005m+7=0;nn+2005n+7=0
(mm+2004m+6)(nn+2006n+8)
=(mm+2005m+7-m-1)(nn+2005n+7+n+1)
=(0-m-1)(0+n+1)
=-(m+1)(n+1)
=-(mn+m+n+1)
=-(7-2005+1)
=1997