计算:3y/(2x+2y) +2xy/x²+xy
1个回答
3y/(2x+2y) +2xy/x²+xy
=3y/2(x+y)+2xy/x(x+y)
=3xy+4xy/2x(x+y)
=7xy/x+y
相关问题
①计算:(-x2+2xy-y2)-2(xy-3x2)+3(2y2-xy)
计算:-2y³+(3xy²-x²y)-2(xy²-y³)
计算5x^3y*(-3y)^2+(-6xy)^2*(-xy)-xy^3(-4x)^2
计算:(1)(2xy2)2•(-3xy3);(2)(2x-3y)(x+2y)-(x+y)2.
计算:(x|x^2-xy)^﹣3×(﹣x^2-2xy+y^2)﹣2÷(x^2|xy-y^2)^2=
有这样一道题,计算:(x﹣y)[(x+y) 2 ﹣xy]﹣(x﹣y)[(x﹣y) 2 +xy]﹣2xy(x﹣y)+3x
(-x²+2xy-y的平方)-2(xy—3x²)+3(2y的平方-xy) 计算.
计算(3xy-2x²+1/2y²)(3xy+2x²-1/2y²)
计算:(1)(√xy+2√y/x+√x/y+√1/xy)√xy (2)(√5-√3)^2-(√5+√3)^2
计算:2x∧2 y*(-4y)∧2+(-2xy)∧2 *y-3xy*4xy∧2