Question

求y=ln(sin2x+2^x)的导数

Answer 1

y=ln(sin2x+2^x)

y'=1/(sin2x+2^x) * (sin2x + 2^x)'

=1/(sin2x+2^x) * (cos2x * (2x)' + ln2 * 2^x)

=(2cos2x + ln2 * 2^x) / (sin2x+2^x)