S12-S9=a10+a11+a12=3(a1+10d)=0
故d=-a1/10
因为a10
Sn=na1+n(n-1)d/2=-10dn+(n^2-n)d/2=d/2[n-21/2]^2-441d/8
n=10或n=11时Sn取得最小,故S10=S11,为最小.
S12-S9=a10+a11+a12=3(a1+10d)=0
故d=-a1/10
因为a10
Sn=na1+n(n-1)d/2=-10dn+(n^2-n)d/2=d/2[n-21/2]^2-441d/8
n=10或n=11时Sn取得最小,故S10=S11,为最小.