原式=x(x+y)/(x+y)(x-y)-y(x-y)/(x+y)(x-y)+2xy/(x+y)(x-y)
=(x²+xy-xy+y²+2xy)/(x+y)(x-y)
=(x²+2xy+y²)/(x+y)(x-y)
=(x+y)²/(x+y)(x-y)
=(x+y)/(x-y)
(x/x-y)-(y/x+y)+(2xy/x^2-y^2)
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