A={x|x^2-x-2>0,x∈R}={x|x<-1或x>2}B={x|2x^2+(5+2a)x+5a<0,x∈R}2x^2+(5+2a)x+5a<0(x+a)(2x+5)<0分类讨论:(i)若-a<-5/2,即a>5/2则B={x|-a<x<-5/2}显然不符合A∩B∩Z={-2}(ii)若-a=-5/2,即a=5/2则B是空...
若集合A={x|x^2-x-2>0,x∈R},B={x|2x^2+(5+2a)x+5a0,x∈R},B={x|2x^2+
2个回答
相关问题
-
若集合A={x|x^2-2ax+a=0,x属于R},B={x|x^2-4x+a+5=0},x属于R}
-
设集合A={X|X²-3X+2=0,X∈R},B={X|2X²-aX+2=0,X∈R}若A∪B=A,
-
集合U=R,A={x|x^2-2x-3>0},B={x|x^2-6x+5≤0}求A∩B,A∪B
-
设集合A={x|x2-3x+2=0},B={x|x2+2(a+1)x+(a2-5)=0},若U=R,A∩(∁UB)=A,
-
设集合A={x|x2-3x+2=0},B={x|x2+2(a+1)x+(a2-5)=0},若U=R,A∩(∁UB)=A,
-
设集合A={x|x2-3x+2=0},B={x|x2+2(a+1)x+(a2-5)=0}.若U=R,A∪(CuB)=A,
-
设集合A={x|x^2+4x=0,x属于R},B={x|x^2+2(a+1)x+a^2 -1=0,x属于R},若A∩B=
-
设集合A={X|X²-3X+2≤0,X∈R},B={X|X²-2aX+2≤0,X∈R}若B属于A 求
-
若集合A={x/x∧2-3x+2=0,x∈R} B={0
-
已知集合A={x丨x^2-5x-24<0,x∈R},B={x丨x^2-3ax+2a^2<0,x∈R},若AUB=A,求实