Question

已知弧长为6.8米,弦长为6米,求拱形的高度.

Answer 1

已知弧长为C=6.8米,弦长为L=6米,求拱形的高度H?

弧半径为R.

Rn+1=(1+(L-2*Rn*SIN(C/(2*Rn)))/(L-C*COS(C/(2*Rn))))*Rn

R0=4

R1=3.973

R2=3.973

R=3.973米

H=R-(R^2-(L/2)^2)^0.5

=3.973-(3.973^2-(6/2)^2)^0.5

=1.368米