Question

已知a为第四象限角,且cosa=(1/2),求1+(tan^2)*a+1/(tan^2)的值

Answer 1

a为第四象限角,且cosa=(1/2),所以sina=-√(1-(cos^2)a)=-√3/2

tana=sina/cosa=-√3

1+(tan^2)*a+1/(tan^2)a

=1+(-√3)^2+1/(-√3)^2

=1+3+1/3

=13/3