将f(x)看成两项的积
即f(x)=X [(x-1)(x-2)……(x-100)]
那f'(x)=x' [(x-1)(x-2)……(x-100)]+x [(x-1)(x-2)……(x-100)]'
=(x-1)(x-2)……(x-100)+x [(x-1)(x-2)……(x-100)]'
后面这个导数不用求出来
所以f'(0)=(-1)(-2)……(-100)+0
=100!
将f(x)看成两项的积
即f(x)=X [(x-1)(x-2)……(x-100)]
那f'(x)=x' [(x-1)(x-2)……(x-100)]+x [(x-1)(x-2)……(x-100)]'
=(x-1)(x-2)……(x-100)+x [(x-1)(x-2)……(x-100)]'
后面这个导数不用求出来
所以f'(0)=(-1)(-2)……(-100)+0
=100!