Question

用代数法解下列方程组!4(x-y-1）=3（1-y）-2 x/2+y/3=2

Answer 1

x/2+y/3=2 ,则x=4-2y/3,代入 4(x-y-1）=3（1-y）-2,得

4(4-2y/3-y-1)=3(1-y)-2

则12-20y/3=1-3y

则11=11y/3

解得y=3

代入x=4-2y/3,解得x=2