洛必达法则
当lim(x->无穷)f(x)=无穷
且lim(x->无穷)g(x)=无穷时有:
lim(x->无穷)[f(x)/g(x)]=lim(x->无穷)[f'(x)/g'(x)]
在这段道题中,f(u)=e^u,g(u)=u
而f'(u)=e^u,g'(u)=1
就得到了结论
洛必达法则
当lim(x->无穷)f(x)=无穷
且lim(x->无穷)g(x)=无穷时有:
lim(x->无穷)[f(x)/g(x)]=lim(x->无穷)[f'(x)/g'(x)]
在这段道题中,f(u)=e^u,g(u)=u
而f'(u)=e^u,g'(u)=1
就得到了结论