Question

[(lg√27+lg^8-3lg√10]/lg^(1.2)计算

Answer 1

lg√27=(1/2)lg27=(3/2)lg3,

lg8=3lg2,

3lg√10=(3/2)lg10=3/2,

lg1.2=lg[(3*4)/10]=lg3+lg4-lg10=(lg3)+2(lg2)-1,

[(lg√27)+lg8-(3lg√10)]/lg1.2

=(3/2)[(lg3)+2(lg2)-1]/[(lg3)+2(lg2)-1]

=3/2.