七年级数学题目,求解答要过程~好的给分值~

1个回答

  • 计算:

    -8m²-[4m-2m²-(3m-2m²-7)]

    =-8m²-(4m-2m²-3m+2m²+7)

    =-8m²-4m+2m²+3m-2m²-7

    =(-8m²+2m²-2m²)-4m-7

    =-8m²-4m-7

    3x²-[7x-(4x-3)-2x²]

    =3x²-(7x-4x+3-2x²)

    =3x²-7x+4x-3+2x²

    =(3x²+2x²)+(-7x+4x)-3

    =5x²-3x-3

    1/2(a²-b)+1/3(a-b²)+1/6(a²+b²)

    =1/2a²-1/2b+1/3a-1/3b²+1/6a²+1/6b²

    =(1/2a²+1/6a²)-1/2b+1/3a+(-1/3b²+1/6b²)

    =2/3a²-1/2b+1/3a-1/6b²

    5ab²-3[2a²-2(a²b-2ab²)]

    =5ab²-3(2a²-2a²b+4ab²)

    =5ab²-6a²+6a²b-12ab²

    =(5ab²-12ab²)-6a²+6a²b

    =-7ab²-6a²+6a²b

    先化简,再求值

    1/4(-4x²+2x-8)-(1/2x-1),其中x=1/2

    =-x²+1/2x-2-1/2x+1

    =-x²-1

    =-(1/2)²-1

    =-1/4-1

    =-5/4

    (4a²-3a)-(2a²+a-1)+(2-a²+4a),其中a=-2

    =4a²-3a-2a²-a+1+2-a²+4a

    =(4a²-2a²-a²)+(-3a-a+4a)+(1+2)

    =a²+3

    =(-2)²+3

    =4+3

    =7

    a-2(2a+b)+3(a-b),其中a=-2

    =a-4a-2b+3a-3b

    =(a-4a+3a)-(2b+3b)

    =-5b

    =-5×(-2)

    =10

    4x²-(2x²+x-1)+(2-x²-3x),其中x=-1/2

    =4x²-2x²-x+1+2-x²-3x

    =(4x²-2x²-x²)-(x+3x)+(1+2)

    =x²-4x+3

    =(-1/2)²-4×(-1/2)+3

    =1/4+2+3

    =21/4

    5(3a²b-ab²)-(ab²+3a²b) 其中a=1/2,b=-1

    =15a²b-5ab²-ab²-3a²b

    =(15a²b-3a²b)-(5ab²+ab²)

    =12a²b-6ab²

    =12×(1/2)²×(-1)-6×1/2×(-1)²

    =12×1/4×(-1)-6×1/2×1

    =-3-3

    =-6

    已知A=4a²+5b,B=-3a²-2b,求2A-B的值,其中a=-2,b=1

    2A-B

    =2(4a²+5b)-(-3a²-2b)

    =8a²+10b+3a²+2b

    =11a²+12b

    =11×(-2)²+12×1

    =11×4+12

    =56

    已知(x+1)²+|y-1|=0,求2(xy-5xy²)-(3xy²-xy)的值

    ∵(x+1)²+|y-1|=0

    ∴x+1=0 且 y-1=0

    ∴x=-1,y=1

    2(xy-5xy²)-(3xy²-xy)

    =2xy-10xy²-3xy²+xy

    =3xy-13xy²

    =3×(-1)×1-13×(-1)×1²

    =-3+13

    =10

    已知 A=x³+2x²y+2y³-1,B=3+y³+2x²y+2x³,若A+B+C=0,求C

    A+B+C=0

    C=-(A+B)

    C=-(x³+2x²y+2y³-1+3+y³+2x²y+2x³)

    =-x³-2x²y-2y³+1-3-y³-2x²y-2x³

    =-(x³+2x³)-(2x²y+2x²y)-(2y³+y³)+(1-3)

    =-3x³-4x²y-3y³-2