Question

解关于x的不等式（ax+1）/(x+a)>1 a的绝对值不等于1

Answer 1

(ax+1)/(x+a)-1＞0

[(ax+1)-(x+a)]/(x+a)＞0

(a-1)(x-1)/(x+a)＞0

1.a＞1时

(x-1)/(x+a)＞0

x＞1 或者x＜-a

2.-1＜a＜1时

(x-1)/(x+a)＜0

-a＜x＜1

3 .a＜-1时

(x-1)/(x+a)＜0

1＜x＜a