Question

若/a-1/+(b-2)的平方=0,A=3a的平方-6ab+b的平方,B=-a的平方-5,求A-B的值

Answer 1

a-1=0

a=1

b-2=0

b=2

A-B

=3a^2-6ab+b^2+a^2+5

=4a^2-6ab+b^2+5

=4-6*2+4+5

=13-12

=1