弧长C=4m,弦高H=1m,求弦长L?
弧半径为R,弧所对圆心角为A.
Rn+1=(1-(Rn*COS(C/(2*Rn))-Rn+H)/((C/2)*SIN(C/(2*Rn))-H))*Rn
R0=2
R1=1.764
R2=1.802
R3=1.803
R4=1.803
半径R=1.803m
A=C/R
=4/1.803
=2.2185弧度
=2.2185*180/PI
=127.11度
L=2*R*SIN(A/2)
=2*1.803*SIN(127.11/2)
=1.844m
弧长C=4m,弦高H=1m,求弦长L?
弧半径为R,弧所对圆心角为A.
Rn+1=(1-(Rn*COS(C/(2*Rn))-Rn+H)/((C/2)*SIN(C/(2*Rn))-H))*Rn
R0=2
R1=1.764
R2=1.802
R3=1.803
R4=1.803
半径R=1.803m
A=C/R
=4/1.803
=2.2185弧度
=2.2185*180/PI
=127.11度
L=2*R*SIN(A/2)
=2*1.803*SIN(127.11/2)
=1.844m