x^4+4x^3+3x^2-4x-4=(x^2-1)(x^2+4)+4x(x^2-1)=(x^2-1)(x^2+4x+4)=(x+1)(x-1)(x+2)^2
x^4+4x^3+3x^2-4x-4
2个回答
相关问题
-
x1+5x2+2x3-4x4=3 -3x1-2x2+3x3+4x4=-6 -x1+3x2-x3-4x4=-2 -2x1+
-
(1)y=x^2-7x=6 (2)y=3x^4+4x^3 (3)y=x^3-x^2-4x+4 (4)y=2x^2-x^4
-
3x4+2x3+3x2+4x-4=0
-
化简4X(2x-2)+(4—3x)、4X(2x-2)-(4-3x)
-
解线性方程组x1+x2+3x3+4x4=5 2x1+4x2+4x3+6x4=8 -x1-2x2-x3-2x4=-3
-
x3+x2--4x--4不能等于x3--(x2+4x+4)吗
-
若2x2-x=1,则4x4-4x3+3x2-x+4=
-
计算①x²-4/x²-4x+3÷x²+3x+2/x²-x②2x+6/4-4x+x
-
15x(3x-8)-4X(2X+3)=6X(4X-4)-4
-
若x>0,则(2x^1/4 + 3^3/2)(2x^1/4 – 3^3/2) – 4x^-1/4(x^3/4 – x^1