Question

因式分解：(a^2+b^2-c^2)-4a^2b^2

Answer 1

(a^2+b^2-c^2)^2-4a^2b^2

=(a^2+b^2-c^2)^2-(2ab)^2

=(a^2+b^2-c^2+2ab)(a^2+b^2-c^2-2ab)

=[(a+b)^2-c^2][(a-b)^2-c^2]

=(a+b+c)(a+b-c)(a-b+c)(a-b-c)