∵BD=DE∴∠DBC=∠DEC,
∵CD=CE∴∠CDE=∠DEC.∴∠DBC=∠DEC=∠CDE.
∵∠BCD=∠CDE+∠DEC=2∠DBC,BD⊥AC.
∴∠DCB=60º,∵AB=AC.
∴△ABC是等边三角形,∴BD垂直平分AC,AD=DC.
∴AD=CE.
∵BD=DE∴∠DBC=∠DEC,
∵CD=CE∴∠CDE=∠DEC.∴∠DBC=∠DEC=∠CDE.
∵∠BCD=∠CDE+∠DEC=2∠DBC,BD⊥AC.
∴∠DCB=60º,∵AB=AC.
∴△ABC是等边三角形,∴BD垂直平分AC,AD=DC.
∴AD=CE.