计算:(x-y)^7/(y-x)^6+(-x-y)^3/(x+y)^2
1个回答
(x-y)^7/(y-x)^6+(-x-y)^3/(x+y)^2
=(x-y)^7/(x-y)^6-(x+y)^3/(x+y)^2
=x-y-(x+y)
=x-y-x-y
=-2y
相关问题
计算(x-y)^7÷(y-x)^6+9-x-y)^3÷(x+y)^2
计算:6x²y+2xy-3x²y²-7x-5yx-4y²x²-6x²y
计算(x^8-x^7y+x^5y^3-x^4y^4+x^3y^5-x^y^7+y^8)(x^2+xy+y^2)
计算:(3x-4y)-[-(2y+x)+(x-3y)]-6x
计算 3(2x-7y)(7y+2x)+(4x+5y)(-5y-4x)
1、(2x+3y)(3x-5y)-(x+y)(6x-7y)
3x+5y-(x+y)=6 2(x+y)-3x=-7
①、计算8(x+y)^8(x-y)^6除[2(x+y)^3·(x-y)^3]^2=?
计算:(1)(-7x2-8y2)•(-x2+3y2)=______;(2)(3x-2y)(y-3x)-(2x-y)(3x
计算或化简:(1) ;(2) ;(3)﹣12x+6y﹣3+10x﹣2﹣y;(4)(2x﹣3y+7)﹣(﹣6x+5y+2)