OK,我来说明,令g(x)=x^(1/2)
由链式法则
y=f(g(x))的导数为
y'=f'(g(x))*g'(x)
=f'(x^(1/2))*(x^(1/2))'
=1/2*x^(-1/2)*f'(x^(1/2))
设f(x)是可导函数,y=f(根号下x),则dy/dx=?,是y和x分别求导,然后二者相除,还是大的导完导小的
OK,我来说明,令g(x)=x^(1/2)
由链式法则
y=f(g(x))的导数为
y'=f'(g(x))*g'(x)
=f'(x^(1/2))*(x^(1/2))'
=1/2*x^(-1/2)*f'(x^(1/2))