Question

计算：(1)（m-n)^2*(n-m)^5*(m-n)^5 (2)(-x)^2*x^3+2x^3*(-x）^2-x*x^

Answer 1

(1)(m-n)^2*(n-m)^5*(m-n)^5

=(m-n)^2*[-(m-n)^5]*(m-n)^5

=-(m-n)^(2+5+5)

=-(m-n)^12

(2)(-x)^2*x^3+2x^3*(-x）^2-x*x^4

=x^2*x^3+2x^3*x^2-x^5

=x^5+2x^5-x^5

=2x^5