(2x+1)/(x+2) + (x+2)/(2x-1)=2
设 (2x+1)/(x+2) = y
则有y + 1/y = 2
两边同时乘乘y
y^2 + 1 = 2y
y^2 - 2y + 1 = 0
(y-1) ^ 2 = 0
解得 y = 1
即(2x+1 )/ (x+2) = 1
2x + 1 = x+2
解得:x = 1
(2x+1)/(x+2) + (x+2)/(2x-1)=2
设 (2x+1)/(x+2) = y
则有y + 1/y = 2
两边同时乘乘y
y^2 + 1 = 2y
y^2 - 2y + 1 = 0
(y-1) ^ 2 = 0
解得 y = 1
即(2x+1 )/ (x+2) = 1
2x + 1 = x+2
解得:x = 1