Question

y=sinx/1+cosx求微分

Answer 1

y' = (sinx/1+cosx)' = (cosx*(1+cosx) -(sinx*-sinx))/(1+cosx)^2

= (cosx+1)/(1+cosx)^2

= 1/(1+cosx)

所以dy = 1/(1+cosx) dx

也可以先化简在求微分