Question

1：(2+1)(2`2+1)(2`4+1)(2`8+1) 用平方差公式计算!2：若x(x-1)-(x`2-y`2)=4,

Answer 1

(2+1)(2`2+1)(2`4+1)(2`8+1) =(2-1)(2+1)(2`2+1)(2`4+1)(2`8+1) =(2`2-1)(2`2+1)(2`4+1)(2`8+1)

= (2`4-1)(2`4+1)(2`8+1)=(2`8-1)(2`8+1)=2`16-1

第二题我实在是无能为力～