(1)已知cosa=4/5,求(sina)^4+(cosa)^4

1个回答

  • (1)因为cosa=4/5,所以(cosa)^2=16/25,(sina)^2=9/25

    (sina)^4+(cosa)^4

    =[(sina)^2+(cosa)^2]^2-2(sina)^2(cosa)^2

    =1-2 * 9/25 * 16/25

    =337/625

    (2)因为sina+cosa=1/2,所以(sina+cosa)^2=1/4

    (sina)^2+(cosa)^2+2*sina*cosa=1+sin2a=1/4

    所以sin2a=-3/4

    (3)[sin(a/2)]^2+[cos(a/2)]^2=1,2sin(a/2)cos(a/2)=sina

    [根号(1-sina)]+[根号(1+sina)]

    =根号{[sin(a/2)]^2+[cos(a/2)]^2-2sin(a/2)cos(a/2)}+根号{[sin(a/2)]^2+[cos(a/2)]^2+2sin(a/2)cos(a/2)]}

    =根号{[sin(a/2)-cos(a/2)]^2}+根号{[sin(a/2)+cos(a/2)]^2}

    因为a属于(1.5派,2派),所以a/2属于(3/4派,派),

    所以sin(a/2)-cos(a/2)>0,sin(a/2)+cos(a/2)