4*2^n*2^n-1
=2^2*2^n*2^n-1
=2^2n+1
(-x)³*x^2n-1+x^2n*x²
=-x^2n+2+x^2n+2
=0
4*2^n*2^n-1 (-x)³*x^2n-1+x^2n*x²
1个回答
相关问题
-
1X2X3+2X3X4+.+n(n+1)(n+2)
-
1x2x3+2x3x4+.+n(n+1)(n+2)=?
-
单项式乘以多项式(x^n-x^n-1+x)*x^n+1(x^2n+1)(-x^2n)(+x^n+2)
-
证明(x+1/x)^n-(x^n+1/x^n)>=2^n-2
-
二项式定理题：求(1+x)^2n+x(1+x)^(2n-1)+x^2(1+x)^(2n-2)+……+x^n(1+)^n展
-
因式分解：2x^n-4x^n-1-8x^n-2
-
(x^n-1)^2*(x^2)^2-n*(-x^n)
-
x^n-1(3x^n+4x^n+1-5x^n+2)
-
Sn=1/(1x2x3)+1/(2x3x4)+...+1/(n(n+1)(n+2))
-
x^n+x^n-1y+x^n-2y^2+.+x^2y^n-2 +xy^n-1 +y^n=?