设所取K2SO4溶液,Al2(SO4)3溶液和蒸馏水三者的体积V1,V2,V3
n(k+)=0.02V1 (K2SO4~~~~2K+)
n(Al3+)=0.04V2 (Al2(SO4)3~~~~~2Al3+)
n(SO42-)=0.01V1+0.06V2
那么:
c(k+)=0.02V1/(V1+V2+V3)=0.01 ①
c(Al3+)=0.04V2/(V1+V2+V3)=0.01 ②
c(SO42-)=(0.01V1+0.06V2)/(V1+V2+V3)=0.02 ③
①/②得出:V1=2V2
带入③:
8V2=6V2+2V3 得到V2=V3
所以V1:V2:V3=2V2:V2:V2=2:1:1