已知x^2-7xy+12y^2=0,求证:x=3y或x=4y.
1个回答
∵x^2-7xy+12y^2=0
十字相乘得:(X-3y)(x-4y)=0
∴(X-3y)=0或(x-4y)=0
x=3y或x=4y
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