1、设小方原有图书x本,则小敏原有图书(5/4)x
x-10 = (7/10)[(5/4)x-10]
x = 24
2、设总重量是x克,则甲是(4/5)x克,乙是(1/5)x克
[(4/5)x - 10] :[(1/5)x + 10] = 7 :5
x = 600/13
3、设这本故事书友x页
x/12 - x/(12+8) = 2
x = 60
4、设甲数是x,则乙数是(x-1)/5,丙数是5x+1
x + (x-1)/5 + 5x+1 = 100
x = 16
(x-1)/5 = 3
5、设乙书架原有x本,则甲书架原有(5/6)x
(5/6)x - 154 = 4/7(x-154)
x = 252
(5/6)x = 210