(1){x+2y+3z=14① {2x+y+z=7②{3x+y+2z=11③

1个回答

  • (1)①×2-②:

    3y+5z=21 ④

    ①×3-③:

    5y+7z=31 ⑤

    ④×5-⑤×3:

    z=3,代入前面④ y=2,x=1.

    (2)①不对,应该是:

    (x-3)/2+3≥x+1

    x-3+6≥2x+2

    x≤1

    ② 1-3x+3<8-x,

    3x-x>1+3-8

    2x>-4,

    ∴x>-2.

    -2<x≤1

    (3)①x-5>1+2x

    x<-6

    ②3x+2<4x

    4x-3x>2

    x>2

    没有公共部分.

    (4)(√0.01+³√0.001)×√144

    =0.1×0.1×12

    =0.12

    (5)|√2-√5|-|√5+√2|

    =√5-√2-(√5+√2)

    =√5-√2-√5-√2

    =-2√2.